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Copy a file with WMI

A question came up on the forum about copying files with CIM (WMI). I normally use Copy-Item rather than CIM as its easier. The questioner was using CIM_LogicalFile when I’ve normally used CIM_DataFile so I decided to take a look at the class. In reality the two classes are very similar and CIM-datafile could be substituted for CIM_LogicalFile in the code that follows.

 

The obvious starting point is to use the Copy method on the CIM_LogicalFile class

 

$files = Get-WmiObject -Class CIM_LogicalFile -Filter "Path = '\\Test\\' AND Extension = 'txt'"

foreach ($file in $files) {
$newfile = "C:\Test2\$($file.FileName).$($file.Extension)"
 
$file.Copy($newfile)

}

 

Couple of points to note. In the Path part of the filter you have to escape the \ delimiter.  Extension doesn’t include the ‘.’

You have to give the full path – including file name - to the loaction to which you want to copy the file. In this case you don’t have to escape the \ delimiter. Consistency is a wonderful thing and usually absent from WMI.

 

You can also use Invoke-WmiMethod

 

$files = Get-WmiObject -Class CIM_LogicalFile -Filter "Path = '\\Test\\' AND Extension = 'txt'"

foreach ($file in $files) {
$newfile = "C:\Test2\$($file.FileName).$($file.Extension)"
 
Invoke-WmiMethod -InputObject $file  -Name Copy -ArgumentList $newfile

}

 

OR

use the new CIM cmdlets

 

$files = Get-CimInstance -ClassName CIM_LogicalFile -Filter "Path = '\\Test\\' AND Extension = 'txt'"

foreach ($file in $files) {
$newfile = "C:\Test2\$($file.FileName).$($file.Extension)"
 
Invoke-CimMethod -InputObject $file  -MethodName Copy -Arguments @{Filename = $newfile}

}

 

In this case you have to give the argument name for the method as well as its value. You can discover the method parameters using Get-CimClass

 

$class = Get-CimClass CIM_LogicalFile

£> $class.CimClassMethods["Copy"].Parameters

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